Question

Find hypotenuse & perimeter of Δ ABC, where AB = 1 cm & BC = 2cm.
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Answer 1

Question:-

Find hypotenuse & perimeter of Δ ABC, where AB = 1 cm & BC = 2cm.

Solution:-

We use Pythagoras theorem

=> ( AC )² = ( AB )² + ( BC )²

=> ( AC )² = ( 1 )² + ( 2 )²

=> ( AC )² = 1 + 4

=> ( AC)² = 5

=> AC = √5 cm

=>Perimeter of Δ ABC = AB+BC+AC

=>Perimeter of Δ ABC = 1+2+√5

=>Perimeter of Δ ABC = 3+√5 cm

Hence Hypotenuse & Perimeter are

√5 cm & 3+√5cm respectively.

i hope it helps you.