Question

Find hypotenuse & perimeter of Δ ABC, where AB = 5cm & BC = 6cm.​

Answer 1

Question:-

Find hypotenuse & perimeter of Δ ABC, where AB = 5 cm & BC = 6 cm.

Solution:-

We use Pythagoras theorem

=> ( AC )² = ( AB )² + ( BC )²

=> ( AC )² = ( 5 )² + ( 6 )²

=> ( AC )² = 25 + 36

=> ( AC)² = 61

=> AC = √61 cmq

=>Perimeter of Δ ABC = AB+BC+AC

=>Perimeter of Δ ABC = 5+6+√61

=>Perimeter of Δ ABC = 11+√61 cm

Hence Hypotenuse & Perimeter are √61 cm & 11+√61cm respectively.

i hope it helps you.

Answer 2

Question:-

Find hypotenuse & perimeter of A ABC, where AB = 5 cm & BC = 6 cm.

Solution:-

We use Pythagoras theorem => ( AC )² = ( AB )² + ( BC )²

=> ( AC )² = ( 5 )² + ( 6 )²

=> ( AC )² = 25 + 36

=> ( AC)? = 61

=> AC = $\sqrt{61 \: cm}$

=>Perimeter of A ABC = AB+BC+AC

=>Perimeter of A ABC = 5+6+v61

=>Perimeter of A ABC = 11+$\sqrt{61 \: cm}$

Hence Hypotenuse & Perimeter are v61 cm & 11+v61cm respectively. i hope it helps you.