Question

Find hypotenuse of triangle if perpendicular =6 and breadth=2. (according to pythagoras theorem) ​

Answer 1

Answer:

$\sqrt{40}$

Step-by-step explanation:

Hypotenuse² = leg₁² + leg₂²

= 6² + 2²

Hypotenuse = $\sqrt{6^2 + 2^2}$

= $\sqrt{40}$

Hope it helps u

Answer 2

Answer:

$2 \sqrt{10}$

Step-by-step explanation:

Given:

Perpendicular = 6

Breadth = 2

According to the Pythagoras theorem:

Perpendicular² + Breadth² = Hypotenuse²

= 6² +2²

= 36 + 4

= 40

Hence,

${hypotenuse}^{2} = 40 \\ hypotenuse = \sqrt{40} \\ = 2 \sqrt{10}$

Hope it helps!