Find hypotenuse or perpendicular. (show the calculation)
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Let PQR be a right angle △, right angled at θ such that,
⇒PQ= Perpendicular
⇒PR= Hypotenuse
⇒QR= Base
⇒A= angles between base (QR) & (PR) hypotenuse.
∴sinA=hypotenusePerpendicular=PRPQ
Hence, the answer is PRPQ.
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