Question

Find i) 24th term of the A.P. 5, 8, 11, 14... 1
ii) 5th term of the A.P. 21, 16, 11, 6, ...

Answer 1

tn=a+(n-1)d
t24=5+(24-1)3
=5+23×3
=74
t5=21+(5-1)-3
=21+4+-3
=9
hope it helps
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Answer 2

Answer:

(i)24th term is 74

(ii)5th term is 1

Step-by-step explanation:

(i)In this question,

We need to find the 24th term of the A.P

Formula for nth term of the A.P

$a_{n}\ =\ a\ +\ (n-1)d$

Here, a = 5 ,d = 3, n = 24

Putting the values we get,

$a_{24}\ =\ 5\ +\ (24-1)3$

$a_{24}\ =\ 5\ +\ (23)3$

$a_{24}\ =\ 5\ + 69$

$a_{24}\ =\ 74$

Hence, 24th term is 74.

(ii) In this we need to find the 5th term of the A.P

Formula for nth term of the A.P

$a_{n}\ =\ a\ +\ (n-1)d$

Here, a = 21, d = -5, n = 5

Putting the values we get,

$a_{5}\ =\ 21\ +\ (5-1)(-5)$

$a_{5}\ =\ 21\ +\(4)(-5)$

$a_{5}\ =\ 21\ -\21$

$a_{5}\ =\ 1$

Hence 5th term of the A.P is 1