Math, asked by ananyabhuyan378, 6 months ago

find

I. (32)½
ii. (16)¾

Answers

Answered by Thinkab13
6

Answer:

1 -

 = \sf{(32)}^{(\frac{1}{2})}

 =\sf{(2^5)}^{(\frac{1}{2})}

 = \sf{(2)^{\frac{5}{2}}}

 = \sf{(\sqrt2)}^{(5)}

 = \sf{4√2}

2 -

 = \sf{(16)}^{(\frac{3}{4})}

 = \sf{(2^4)}^{(\frac{3}{4})}

 = \sf{2^3}

 = \sf{8}

Answered by mathdude500
1

\begin{gathered}\begin{gathered}\bf  To \:  Find :-  \begin{cases} &\sf{ {32}^{ \frac{1}{2} } } \\ &\sf{ {(16)}^{ \frac{3}{4} } }  \end{cases}\end{gathered}\end{gathered}

\large\underline\purple{\bold{Solution :-  }}

\bf \:\large \red{AηsωeR : i.} ✍

 \tt \:  ⟼  \:  {32}^{ \frac{1}{2} }

 \tt \:  ⟼  {(2 \times 2 \times 2 \times 2 \times 2)}^{ \frac{1}{2} }

 \tt \:  ⟼ 2 \times 2 \times  {(2)}^{ \frac{1}{2} }

 \tt \:  ⟼   4 \sqrt{2}

\bf \:\large \red{AηsωeR : ii.} ✍

 \tt \:  ⟼  {(16)}^{ \frac{3}{4} }

 \tt \:  ⟼  {(2 \times 2 \times 2 \times 2)}^{ \frac{3}{4} }

 \tt \:  ⟼  {(2)}^{4 \times  \frac{3}{4} }

 \tt \:  ⟼  {2}^{3}

 \tt \:  ⟼ 8

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