Question

find (i)√5 * sin18°/cos72°
(ii)(cos 15° - cos 75°) : (sin 75° - sin 15°)​

Answer 1

Step-by-step explanation:

1)√5*sin18°/cos72°

√5*(sin18°/sin(90-72)°

√5*(sin18°/sin18°)

√5*1

√5

2)(cos15-cos75):(sin75-sin15)

(cos15-cos75):(sin(90-75)-sin(90-15)

(cos15-cos75):(cos15-cos75)