Math, asked by jeetp25605, 2 months ago

Find :(i) 81½ (ii)243⅕(iii)343⅓ (IV)625¼(v)256⅛(vi)729⅙

Answers

Answered by saidhu77224gmailcom

0

Answer:

ksjjsjzjzjususuusususususususyusussuyssyte

Step-by-step explanation:

nsnsmsnsjsjsjdsjjssksksjsjejejejeieieieirkrkrkdjfkfmfmfmkfof

Answered by rajeebsc001

2

Answer:

(i) 81½ = (9²)¹/² = 9

(ii)243⅕ = (3^5)¹/5 = 3

(iii)343⅓ = (7^3)¹/³ = 7

(IV)625¼ = (5^4)¼ = 5

(v)256⅛ = (2^8)⅛ = 2

(vi)729⅙ = (3^6)⅙ = 3

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