Find :(i) 81½ (ii)243⅕(iii)343⅓ (IV)625¼(v)256⅛(vi)729⅙
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Answer:
(i) 81½ = (9²)¹/² = 9
(ii)243⅕ = (3^5)¹/5 = 3
(iii)343⅓ = (7^3)¹/³ = 7
(IV)625¼ = (5^4)¼ = 5
(v)256⅛ = (2^8)⅛ = 2
(vi)729⅙ = (3^6)⅙ = 3
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