Question

find:
I) 9power 3/2
125power -1/3

Pls do the sum and tell ​

Answer 1

${9}^{ \frac{3}{2} } = ( {3}^{2} ) ^{ \frac{3}{2} } = {3}^{3} = 27$

${125}^{ \frac{ - 1}{3} } = (5 ^{3} ) ^{ \frac{ - 1}{3} } = {5}^{ - 1} = \frac{1}{5}$

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Answer 2

Answer:

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Step-by-step explanation: