Math, asked by kourrosy49, 6 months ago

find:- (i) (a-2c)²
(ii) (3s - 5)²
(iii) (3 - 4x²)²​

Answers

Answered by kulkarninishant346
1

Answer:

Step-by-step explanation:

i)  

(x+1)  

2

=2(x−3)  

x  

2

+2x+1=2x−6

x  

2

+7=0   → Quadratic

ii)  

x  

2

−2x=−2(3−x)

x  

2

−2x=−6+2x

x  

2

+4x+6=0   → Quadratic

iii)  

(x−2)(x+1)=(x−1)(x+3)  

x  

2

−x−2=x  

2

+2x−3  

3x=1   → Non Quadratic

iv)  

(x−3)(2x+1)=(x)(x+5)

2x  

2

−5x−3=x  

2

+5x

x  

2

+10x−3=0   → Quadratic

v)  

(x−3)(2x−1)=(x−1)(x+5)

2x  

2

−7x+3=x  

2

+4x−5

x  

2

−11x+8=0   → Quadratic

vi)  

x  

2

+3x+1=(x−2)  

2

 

x  

2

+3x+1=x  

2

−4x+4

7x=3   → Non Quadratic

vii)  

(x+2)  

3

=2x(x  

2

−1)

x  

3

+8+6x(x+2)=2x  

3

−2x

x  

3

+8+6x  

2

+12x=2x  

3

−2x

−x  

3

+6x  

2

+14x+8=0   → Non Quadratic

viii)  

x  

3

−4x  

2

−x+1

=x  

3

+3x  

2

(−2)+3x(−2)  

2

+(−2)  

3

 

x  

3

−4x  

2

−x+1=x  

3

−6x  

2

+12x−8

x  

3

−4x  

2

−x+1−x  

3

+6x  

2

−12x+8=0

2x  

2

−13x+9=0   → Non Quadratic

Answered by MrAadil
2

If u got it then mark me as BRAINLIST and FOLLOW me and LIKE my answer.

Attachments:
Similar questions