Find í in the circuit when the source
voltage Vs = 50 cos 200t volts.
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We have to find the current in the circuit when the source voltage Vs = 500 cos200t volts.
Solution : given, capacitive reactance, XC = 1/jωC
Here, ω = 200 rad/s, C = 5mF = 5 × 10¯³ F
So, XC = 1/j200×5×10¯³ = 1/j = -j
now inductive reactance, XL = jωL
here, L = 20mH = 20 × 10¯³ H
so, xL = j × 200 × 20 × 10¯³ = j4
Now, Zin = R + XC + XL
= 10 - j + j4
= 10 + j3
Now, i = Vs/Zin
= (50 < 0°)/(10 + j3)
= 4.789 < - 16.7°
Therefore the current is 4.789cos(200t - 16.7°)
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