find I'm each case the smallest perfect square divisible by the given number
2,4 and 5
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Q9) Find the smallest square number that is divisible by each of the numbers 4, 9 and 10.
Solution
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Solution:
L.C.M. of 4, 9 and 10 is 180.
Prime factors of 180 = 2 x 2 x 3 x 3 x 5
Here, prime factor 5 has no pair. Therefore 180 must be multiplied by 5 to make it a perfect square.
\therefore180\times5=900∴180×5=900
Hence, the smallest square number which is divisible by 4, 9 and 10 is 900.
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