Question

Find (i) sinC (ii) cosC and (iii) tanC in the adjacent triangle​

Answer 1

Answer:

ac is tan cb is sin and Ab is cos

Answer 2

Answer:

sinC=AB/AC

AC^2=AB^2+BC^2

13×13=AB^2+5×5

169=AB^2+25

AB^2=169-25=144

AB=12

sinC=12/13

cosC=BC/AC=5/13

tanC=AB/BC=12/5