Find (i) the total number of nuetrons, and (ii) the total mass of nuetrons in 7mg of 14c
Answers
Answered by
1
1) No. of atoms of 14C in 1 mole = 6.023*10^23
since one atom of 14C contains (14-6 = 8 neutrons)
so, no. of neutrons in 14 g of 14C =6.023*10^23*8
OR 14g of 14C contains =6.023*10^23*8
so, 7 mg of 14C contains = 2.4092 * 10^21
2) mass of one neutron = 1.67493 * 10^-27 Kg
mass of total neutrons in 7 mg og 14C = (2.4092 * 10^21) (1.67493 * 10^-27) =4.0352 * 10^-6 Kg
since one atom of 14C contains (14-6 = 8 neutrons)
so, no. of neutrons in 14 g of 14C =6.023*10^23*8
OR 14g of 14C contains =6.023*10^23*8
so, 7 mg of 14C contains = 2.4092 * 10^21
2) mass of one neutron = 1.67493 * 10^-27 Kg
mass of total neutrons in 7 mg og 14C = (2.4092 * 10^21) (1.67493 * 10^-27) =4.0352 * 10^-6 Kg
Similar questions