Question

Find (i) the velocity of particle at t=0 and t=3s (ii) the average velocity between t=3s and t=6s​

Answer 1

Answer:

avjspeed=

totaltime

totaldistance

avjvelocity=

totaltime

totaldisplacement

Displacement=Area under graph

Displacement fice t=6s=10×3+

2

1

×10×5−

2

1

×5×1

=45/2+30=105/2

Distance fice t=6s=∣10×3∣+(

2

1

×10×5)+(−

2

1

×5×1)

=30+

2

50

+

2

5

=

2

115

Average speed=distance=115=23

average velocity=distance=105=21