find i1 i2 and i3 by kvl
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In this circuit
I= 2.1 A I₁= 0.9 A I₂=3 A
According to KVL, we have to take two loops here.
Lets say the first loop is ABCFA which is taken clockwise and applying KVL here we get the following equation,
V₁ - 10 I₁ - 2I₂ + V₃ = 0
And the second loop is CDEFC which is taken anti clockwise and applying KVL here we get the following equation,
V₂ - 10 I - 2I₂ + V₃ = 0
By adding these two equation we get,
V₁ + V₂ - 10 (I₁ + I) = 0
By applying KCL in the whole loop, we get, I₁ + I = I₂
By solving these two and putting the values given, we get, I₂ = 3 A
By putting this value in the first and third equation, we get I₁=0.9 A and I=2.1 A
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