Physics, asked by jainprashuk, 5 hours ago

find i1 i2 and i3 by kvl​

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Answered by learnlovely
0

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Answered by mindfulmaisel
0

In this circuit

I= 2.1 A I₁= 0.9 A I₂=3 A

According to KVL, we have to take two loops here.

Lets say the first loop is ABCFA which is taken clockwise and applying KVL here we get the following equation,

V₁ - 10 I₁ - 2I₂ + V₃ = 0

And the second loop is CDEFC which is taken anti clockwise and applying KVL here we get the following equation,

V₂ - 10 I - 2I₂ + V₃ = 0

By adding these two equation we get,

V₁ + V₂ - 10 (I₁ + I) = 0

By applying KCL in the whole loop, we get, I₁ + I = I₂

By solving these two and putting the values given, we get, I₂ = 3 A

By putting this value in the first and third equation, we get I₁=0.9 A and I=2.1 A

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