Find i1/i2
in the given circuit.
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Answer:
i1=in left corner, above 6v
i1=in opposite of left corner above 12 v
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Answer:
resistance across 12 v=1/(1/6+{1/(3+2))=1/{(1/6)+(1/5)}
=30/11
i1=12/(30/11)=12×11/30=4.4 amp
resistance across 6v=1/{1/2+1/(6+3)}
=1/{1/2+1/9}=1/(1/(11/18)/=18/11
i2=6/(18/11)=6×11/18=11/3=3.7 amp
i1/i2=(18/11)/(11/3)=18×3/(11×11)
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