Question

Find i1/i2

in the given circuit.

Answer 1

Answer:

i1=in left corner, above 6v

i1=in opposite of left corner above 12 v

Answer 2

Answer:

resistance across 12 v=1/(1/6+{1/(3+2))=1/{(1/6)+(1/5)}

=30/11

i1=12/(30/11)=12×11/30=4.4 amp

resistance across 6v=1/{1/2+1/(6+3)}

=1/{1/2+1/9}=1/(1/(11/18)/=18/11

i2=6/(18/11)=6×11/18=11/3=3.7 amp

i1/i2=(18/11)/(11/3)=18×3/(11×11)