Find if point (4,-3) lies on the line 2y=ax+6
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Given 2y=ax+6,,, point (4,-3) lies on this line.,,,, so this point must satisfy the equation of given line,,, ie
2(-3)=a(4)+6
-6=4a+6
-6-6=4a
-12=4a
(-12)/4=a
a=(-3)
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Answered by
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Hey
Here is your answer,
The point (4,-3) lies on the line 2y=ax+6, the point 4 lies on x-axis whereas -3 lies on y-axis,
so, x = 4 and y = -3
substitute the values of x and y in the line equation,
2y = ax+6
2(-3) = a(4) + 6
-6 = 4a + 6
moving 6 to left hand side,
- 6 - 6 = 4a
4a = -12
a = -12/4
a = -3
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hope it helps you...
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