Question

Find θ if sin(θ+ 36°) = cos θ, where θ+ 36° is an acute angle. Alse give the solution.

Answer 1

solution is here hope this will help

Answer 2

$\sin( \alpha + 36 ) = \cos( \alpha )$
$\sin( \alpha + 36) = \sin(90 - \alpha )$
$\alpha + 36 = 90 - \alpha \\ 2 \alpha = 90 - 36 \\ \alpha = 54 \div 2 \\ \alpha = 27$