Question

find if x=3 is a root of equation kx square -10x+3=0

Answer 1

↑ Here is your answer ↓ _____________________________________________________________ _____________________________________________________________

$kx^2 -10x + 3 = 0$

$x=3$

$k(3)^2 - 10(3) + 3 = 0$

$9k - 30 + 3 =0$

$9k - 27 = 0$

$9k = 27$

$k = 27/9$

$k=3$

Answer 2

Find :- k

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Given that x =3

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Putting the value of x,

=> Kx² -10x + 3 =0

=> K(3)² -10(3) + 3 = 0

=> K(9) - 30 + 3 = 0

=> 9k - 27 = 0

=> 9k= 27

=> K = 27/9

=> k = 3



I hope this will help you


-by ABHAY