Question

Find imaginary part of Z = (5 - i)/(2 - 3i)

Answer 1

Step-by-step explanation:

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Answer 2

$\frac{5 - i}{2 - 3i} \times \frac{2 + 3i}{2 + 3i} \\ \\ = \frac{10 + 15i - 2i - 3( {i})^{2} }{4 - 9( {i})^{2} } \\ \\ = \frac{10 + 13i - 3( - 1)}{4 - 9( - 1)} \\ \\ = \frac{10 + 13i + 3}{4 + 9} \\ \\ = \frac{13 + 13i}{13} \\ \\ = \frac{13( 1 + i)}{13} \\ \\ = \bf 1 + i$