Question

Find, in ascending powers of x, the first three terms of (a) (1+2x) ^5 and (b) (3-x) ^5. Hence obtain the coefficient of x^2 in the expansion of (3+5x-2x^2) ^5?​

Answer 1

Answer:

$x = 1$

Step-by-step explanation:

$(8x - 2x2)5 \\ 6x2 = 5 \\ 6x = 5 + 2 \\ 6x = 7 \\ x = 7 - 6 \\ x = 1$