Find in each case given below the value of x if : (vi) sin 3x = 2 sin 30° cos 30°
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Answered by
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Answer:
sin3x=2sin30.cos30
sin3x=2(1/2).rootof3/2
sin3x=root3/2=sin60
sin3x=sin60
3x=60
x=20
Answered by
1
Given:
Sin3x = 2 sin30° cos30°
Solution:
→Sin3x = 2sin30° cos30°
→sin3x = 2(1/2) × √3/2
[• we know that sin30°=1/2. and cos30°=√3/2]
→sin3x = 1×√3/2
→sin3x = √3/2
→sin3x = sin60°
[ we know that √3/2 = sin60°]
→3x = sin-¹(sin60°)
→3x = 60°
→x = 60°/3
→x= 20°
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