Math, asked by brajeshguptarlic, 10 months ago

Find in each case given below the value of x if : (vi) sin 3x = 2 sin 30° cos 30°​

Answers

Answered by pokuruvam147
3

Answer:

sin3x=2sin30.cos30

sin3x=2(1/2).rootof3/2

sin3x=root3/2=sin60

sin3x=sin60

3x=60

x=20

Answered by Anonymous
1

Given:

Sin3x = 2 sin30° cos30°

Solution:

→Sin3x = 2sin30° cos30°

→sin3x = 2(1/2) × √3/2

[• we know that sin30°=1/2. and cos30°=√3/2]

→sin3x = 1×√3/2

→sin3x = √3/2

→sin3x = sin60°

[ we know that √3/2 = sin60°]

→3x = sin-¹(sin60°)

→3x = 60°

→x = 60°/3

→x= 20°

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