Find in hectares the area of a rectangle of length 9 dam and breadth 21 CM
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1
Find the area, in square meters, of a rectangle whose
(i) Length = 5.5 m, breadth = 2.4 m
(ii) Length = 180 cm, breadth = 150 cm
A1: We have,
(i) Length = 5.5 m, Breadth = 2.4 m Therefore, Area of rectangle = Length x Breadth = 5.5 m x 2.4 m = 13.2 m2
(ii) Length = 180 cm = 1.8 m, Breadth = 150 cm = 1.5 m [ Since 100 cm = 1 m] Therefore, Area of rectangle = Length x Breadth = 1.8 m x 1.5 m = 2.7 m2
Q2: Find the area, in square centimeters, of a square whose side is
(i) 2.6 cm
(ii) 1.2 dm
A2: We have,
(i) Side of the square = 2.6 cm
Therefore, area of the square = (Side)2 = (2.6 cm)2= 6.76 cm2
(ii) Side of the square = 1.2 dm = 1.2 x 10 cm = 12 cm
Therefore, area of the square = (Side)2 = (12 cm)2= 144 cm2 [ Since 1 dm = 10 cm]
Q3: Find in square metres, the area of a square of side 16.5 dam.
A3: We have,
Side of the square = 16.5
dam = 16.5 x 10 m = 165 m
Area of the square = (Side)2 = (165 m)2 = 27225 m2
[Since 1 dam/dm (decameter) = 10 m ]
Q4: Find the area of a rectangular field in acres whose sides are:
(1) 200 m and 125 m
(ii) 75 m 5 dm and 120 m
A4 : We have,
(i) Length of the rectangular field = 200 m
Breadth of the rectangular field = 125 m
Therefore, Area of the rectangular field = Length x Breadth = 200 m x 125 m
= 25000 m2 = 250 acres [Since 100 m2 = 1 are]
(ii) Length of the rectangular field =75 m 5 dm = (75 + 0.5) m
= 75.5 m [Since 1 dm = 10 cm = OA m]
Breadth of the rectangular field = 120 m
Therefore, Area of the rectangular field = Length x Breadth
= 75.5 m x 120 m = 9060 m2 = 90.6 acres [Since 100 m2 = 1 are]
Q 5: Find the area of a rectangular field in hectares whose sides are:
(i) 125 m and 400 m
(ii) 75 m 5 dm and 120 m
A 5 : We have,
(i) Length of the rectangular field = 125 m
Breadth of the rectangular field = 400 m
Therefore, Area of the rectangular field = Length x Breadth
= 125 m x 400 m = 50000 m2 = 5 hectares [Since 10000 m2 = 1 hectare]
(ii) Length of the rectangular field =75 m 5 dm = (75 + 0.5) m
= 75.5 m [Since 1 dm = 10 cm = 0.1 m]
Breadth of the rectangular field = 120 m
Therefore, Area of the rectangular field = Length x Breadth
= 75.5 m x 120 m = 9060 m2 = 0.906 hectares [Since 10000 m2 = 1 hectare]
Q6: A door of dimensions 3 m x 2m is on the wall of dimension 10 m x 10 m. Find the cost of painting the wall if rate of painting is Rs 2.50 per sq. m.
A 6 : We have,
Length of the door = 3 m
Breadth of the door = 2 m
Side of the wall = 10 m
Area of the wall = Side x Side = 10 m x 10 m
= 100 m2
Area of the door = Length x Breadth = 3 m x 2 m = 6 m
Thus, required area of the wall for painting = Area of the wall – Area of the door
= (100 – 6) m2= 94 m2
Rate of painting per square metre = Rs. 2.50
Hence, the cost of painting the wall = Rs. (94 x 2.50) = Rs. 235
Q7: A wire is in the shape of a rectangle. Its length is 40 cm and breadth is 22 cm. If the same wire is bent in the shape of a square, what will be the measure of each side? Also, find which side encloses more area?
A7 : We have,
Perimeter of the rectangle = 2(Length + Breadth)
= 2(40 cm + 22 cm) = 124 cm
It is given that the wire which was in the shape of a rectangle is now bent into a square.
Therefore, the perimeter of the square = Perimeter of the rectangle
=> Perimeter of the square = 124 cm
4 x side = 124 cm
Side = 124/4 = 31 cm
Now, Area of the rectangle = 40 cm x 22 cm = 880 cm2
Area of the square = (Side)2 = (31 cm)2 = 961 cm2.
Therefore, the square-shaped wire encloses more area.
Q8: How many square metres of glass will be required for a window, which has 12 panes, each pane measuring 25 cm by 16 cm?
A8: We have,
Length of the glass pane = 25 cm
Breadth of the glass pane = 16 cm
Area of one glass pane = 25 cm x 16 cm
= 400 cm2 = 0.04 m2
[Since 1 m2 = 10000 cm2 ]
Thus, Area of 12 such panes = 12 x 0.04 = 0.48 m2
(i) Length = 5.5 m, breadth = 2.4 m
(ii) Length = 180 cm, breadth = 150 cm
A1: We have,
(i) Length = 5.5 m, Breadth = 2.4 m Therefore, Area of rectangle = Length x Breadth = 5.5 m x 2.4 m = 13.2 m2
(ii) Length = 180 cm = 1.8 m, Breadth = 150 cm = 1.5 m [ Since 100 cm = 1 m] Therefore, Area of rectangle = Length x Breadth = 1.8 m x 1.5 m = 2.7 m2
Q2: Find the area, in square centimeters, of a square whose side is
(i) 2.6 cm
(ii) 1.2 dm
A2: We have,
(i) Side of the square = 2.6 cm
Therefore, area of the square = (Side)2 = (2.6 cm)2= 6.76 cm2
(ii) Side of the square = 1.2 dm = 1.2 x 10 cm = 12 cm
Therefore, area of the square = (Side)2 = (12 cm)2= 144 cm2 [ Since 1 dm = 10 cm]
Q3: Find in square metres, the area of a square of side 16.5 dam.
A3: We have,
Side of the square = 16.5
dam = 16.5 x 10 m = 165 m
Area of the square = (Side)2 = (165 m)2 = 27225 m2
[Since 1 dam/dm (decameter) = 10 m ]
Q4: Find the area of a rectangular field in acres whose sides are:
(1) 200 m and 125 m
(ii) 75 m 5 dm and 120 m
A4 : We have,
(i) Length of the rectangular field = 200 m
Breadth of the rectangular field = 125 m
Therefore, Area of the rectangular field = Length x Breadth = 200 m x 125 m
= 25000 m2 = 250 acres [Since 100 m2 = 1 are]
(ii) Length of the rectangular field =75 m 5 dm = (75 + 0.5) m
= 75.5 m [Since 1 dm = 10 cm = OA m]
Breadth of the rectangular field = 120 m
Therefore, Area of the rectangular field = Length x Breadth
= 75.5 m x 120 m = 9060 m2 = 90.6 acres [Since 100 m2 = 1 are]
Q 5: Find the area of a rectangular field in hectares whose sides are:
(i) 125 m and 400 m
(ii) 75 m 5 dm and 120 m
A 5 : We have,
(i) Length of the rectangular field = 125 m
Breadth of the rectangular field = 400 m
Therefore, Area of the rectangular field = Length x Breadth
= 125 m x 400 m = 50000 m2 = 5 hectares [Since 10000 m2 = 1 hectare]
(ii) Length of the rectangular field =75 m 5 dm = (75 + 0.5) m
= 75.5 m [Since 1 dm = 10 cm = 0.1 m]
Breadth of the rectangular field = 120 m
Therefore, Area of the rectangular field = Length x Breadth
= 75.5 m x 120 m = 9060 m2 = 0.906 hectares [Since 10000 m2 = 1 hectare]
Q6: A door of dimensions 3 m x 2m is on the wall of dimension 10 m x 10 m. Find the cost of painting the wall if rate of painting is Rs 2.50 per sq. m.
A 6 : We have,
Length of the door = 3 m
Breadth of the door = 2 m
Side of the wall = 10 m
Area of the wall = Side x Side = 10 m x 10 m
= 100 m2
Area of the door = Length x Breadth = 3 m x 2 m = 6 m
Thus, required area of the wall for painting = Area of the wall – Area of the door
= (100 – 6) m2= 94 m2
Rate of painting per square metre = Rs. 2.50
Hence, the cost of painting the wall = Rs. (94 x 2.50) = Rs. 235
Q7: A wire is in the shape of a rectangle. Its length is 40 cm and breadth is 22 cm. If the same wire is bent in the shape of a square, what will be the measure of each side? Also, find which side encloses more area?
A7 : We have,
Perimeter of the rectangle = 2(Length + Breadth)
= 2(40 cm + 22 cm) = 124 cm
It is given that the wire which was in the shape of a rectangle is now bent into a square.
Therefore, the perimeter of the square = Perimeter of the rectangle
=> Perimeter of the square = 124 cm
4 x side = 124 cm
Side = 124/4 = 31 cm
Now, Area of the rectangle = 40 cm x 22 cm = 880 cm2
Area of the square = (Side)2 = (31 cm)2 = 961 cm2.
Therefore, the square-shaped wire encloses more area.
Q8: How many square metres of glass will be required for a window, which has 12 panes, each pane measuring 25 cm by 16 cm?
A8: We have,
Length of the glass pane = 25 cm
Breadth of the glass pane = 16 cm
Area of one glass pane = 25 cm x 16 cm
= 400 cm2 = 0.04 m2
[Since 1 m2 = 10000 cm2 ]
Thus, Area of 12 such panes = 12 x 0.04 = 0.48 m2
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Secondary School
Math
5 points
Find in hectares the area of a rectangle of length 9 dam and breadth 21 CM
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by Rajdogra72 3 minutes ago
Answers
Expert
Find the area, in square meters, of a rectangle whose
(i) Length = 5.5 m, breadth = 2.4 m
(ii) Length = 180 cm, breadth = 150 cm
A1: We have,
(i) Length = 5.5 m, Breadth = 2.4 m Therefore, Area of rectangle = Length x Breadth = 5.5 m x 2.4 m = 13.2 m2
(ii) Length = 180 cm = 1.8 m, Breadth = 150 cm = 1.5 m [ Since 100 cm = 1 m] Therefore, Area of rectangle = Length x Breadth = 1.8 m x 1.5 m = 2.7 m2
Q2: Find the area, in square centimeters, of a square whose side is
(i) 2.6 cm
(ii) 1.2 dm
A2: We have,
(i) Side of the square = 2.6 cm
Therefore, area of the square = (Side)2 = (2.6 cm)2= 6.76 cm2
(ii) Side of the square = 1.2 dm = 1.2 x 10 cm = 12 cm
Therefore, area of the square = (Side)2 = (12 cm)2= 144 cm2 [ Since 1 dm = 10 cm]
Secondary School
Math
5 points
Find in hectares the area of a rectangle of length 9 dam and breadth 21 CM
Ask for details
Follow
Report
by Rajdogra72 3 minutes ago
Answers
Expert
Find the area, in square meters, of a rectangle whose
(i) Length = 5.5 m, breadth = 2.4 m
(ii) Length = 180 cm, breadth = 150 cm
A1: We have,
(i) Length = 5.5 m, Breadth = 2.4 m Therefore, Area of rectangle = Length x Breadth = 5.5 m x 2.4 m = 13.2 m2
(ii) Length = 180 cm = 1.8 m, Breadth = 150 cm = 1.5 m [ Since 100 cm = 1 m] Therefore, Area of rectangle = Length x Breadth = 1.8 m x 1.5 m = 2.7 m2
Q2: Find the area, in square centimeters, of a square whose side is
(i) 2.6 cm
(ii) 1.2 dm
A2: We have,
(i) Side of the square = 2.6 cm
Therefore, area of the square = (Side)2 = (2.6 cm)2= 6.76 cm2
(ii) Side of the square = 1.2 dm = 1.2 x 10 cm = 12 cm
Therefore, area of the square = (Side)2 = (12 cm)2= 144 cm2 [ Since 1 dm = 10 cm]
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