Physics, asked by jayantjakhar444, 4 months ago

find ß
in P = alpha/bitaa •e^(-apha z /k theta)​

Answers

Answered by suvratraj79922
1

Answer:

Since exponential term is dimensionless,

Dimension of α, [α]=

[Z]

[k][θ]

=

L

(ML

2

T

−2

K

−1

)∗(K)

=MLT

−2

Since

β

α

must have the dimensions of pressure(ML

−1

T

−2

)

Therefore, dimensions of β, [β]=

ML

−1

T

−2

MLT

−2

=L

=2

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