Math, asked by piryagor, 1 year ago

find in quadratic polynomial p(y) whose sum and product of zeroes are 3 and -1/3 respectively

Answers

Answered by Anonymous
1
quadratic eqn= x^2 -(sum of roots )x + product of roots
x^2-3x-1/3

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Answered by Aurora34
0
→We know that,

Sum of zeroes = - b/a


★ 3 X 3/3=9/3 = -b/a

Also,

Product of zeroes= c/a

★ -1/3 = c/a

Now, on comparing it with, ax²+bx+c

We have,

★ 3x²-9x-1
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