Math, asked by alishbaamir1931, 2 months ago

Find indivisible of 2091 in 2,3,5,11

Answers

Answered by harbanskaur959
0

Answer:

indivisible of 2091 are 2, 5 and 11

Step-by-step explanation:

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Answered by cdot58
0
Divisibility by 2:
Last digit should be even. Our number doesn’t meet the requirements to be divisible by 2, hence it is indivisible by 2
Divisibility by 3:
Sum of all digits must be divisible by 3
2+0+9+1 = 12
3 x 4 = 12 hence, it is divisible by 3
Divisibility by 5:
Last digit should be 0 or 5. Our number doesn’t meet the requirements to be divisible by 5, hence it’s indivisible by 5
Divisibility by 11:
Subtract the sum of alternate digits and it should be divisible by 11
2+9 = 11 1 + 0 = 1
11 - 1 = 10
10 isn’t divisible by 11, hence the number is indivisible by 11
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