Find indivisible of 2091 in 2,3,5,11
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Answer:
indivisible of 2091 are 2, 5 and 11
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Divisibility by 2:
Last digit should be even. Our number doesn’t meet the requirements to be divisible by 2, hence it is indivisible by 2
Divisibility by 3:
Sum of all digits must be divisible by 3
2+0+9+1 = 12
3 x 4 = 12 hence, it is divisible by 3
Divisibility by 5:
Last digit should be 0 or 5. Our number doesn’t meet the requirements to be divisible by 5, hence it’s indivisible by 5
Divisibility by 11:
Subtract the sum of alternate digits and it should be divisible by 11
2+9 = 11 1 + 0 = 1
11 - 1 = 10
10 isn’t divisible by 11, hence the number is indivisible by 11
Last digit should be even. Our number doesn’t meet the requirements to be divisible by 2, hence it is indivisible by 2
Divisibility by 3:
Sum of all digits must be divisible by 3
2+0+9+1 = 12
3 x 4 = 12 hence, it is divisible by 3
Divisibility by 5:
Last digit should be 0 or 5. Our number doesn’t meet the requirements to be divisible by 5, hence it’s indivisible by 5
Divisibility by 11:
Subtract the sum of alternate digits and it should be divisible by 11
2+9 = 11 1 + 0 = 1
11 - 1 = 10
10 isn’t divisible by 11, hence the number is indivisible by 11
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