Question

find instantaneous acceleration if x = (t+1/t) ^2​

Answer 1

Answer:

Given that,

X=1+2t+3t

2

….(I)

Now, the acceleration is

Differentiate of equation (I)

x=1+2t+3t

2

v=

dt

dx

=0+2+6t

Now, again differentiate

a=

dt

dv

=

dt

2

d

2

x

=6m/s

2

Hence, the instantaneous acceleration is 6 m/s2

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