find instantaneous acceleration if x = (t+1/t) ^2
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Answer:
Given that,
X=1+2t+3t
2
….(I)
Now, the acceleration is
Differentiate of equation (I)
x=1+2t+3t
2
v=
dt
dx
=0+2+6t
Now, again differentiate
a=
dt
dv
=
dt
2
d
2
x
=6m/s
2
Hence, the instantaneous acceleration is 6 m/s2
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