find integral of (1/2x^2+3) dx
Answers
Answered by
0
This is your answer
Hope it is helpful
Attachments:
Answered by
0
Answer:
2.5x+c
Step-by-step explanation:
Integral of x^n=X^n+1/n+1=for x^-2=x^-1/-1=-1/x=
1/2*(-1/x)+3x+c
3x-0.5x+c
2.5x+c
Similar questions