Find integral roots of polynomial x3 -6x2+11x-6 explain briefly
Answers
Answered by
0
Answer:
The zeros are
1
,
4
and
−
3
Explanation:
Given:
x
3
−
2
x
2
−
11
x
+
12
Sum of coefficients shortcut
Note that the sum of the coefficients is
0
. That is:
1
−
2
−
11
+
12
=
0
Hence,
x
=
1
is a zero and
(
x
−
1
)
a factor:
x
3
−
2
x
2
−
11
x
+
12
=
(
x
−
1
)
(
x
2
−
x
−
12
)
The zeros are
1
,
4
and
−
3
Explanation:
Given:
x
3
−
2
x
2
−
11
x
+
12
Sum of coefficients shortcut
Note that the sum of the coefficients is
0
. That is:
1
−
2
−
11
+
12
=
0
Hence,
x
=
1
is a zero and
(
x
−
1
)
a factor:
x
3
−
2
x
2
−
11
x
+
12
=
(
x
−
1
)
(
x
2
−
x
−
12
)
Answered by
1
e zeros are 1, 4 and −3
Explanation:
Given:
x3−2x2−11x+12
Sum of coefficients shortcut
Note that the sum of the coefficients is 0. That is:
1−2−11+12=0
Hence, x=1 is a zero and (x−1) a factor:
x3−2x2−11x+12=(x−1)(x2−x−12)
Explanation:
Given:
x3−2x2−11x+12
Sum of coefficients shortcut
Note that the sum of the coefficients is 0. That is:
1−2−11+12=0
Hence, x=1 is a zero and (x−1) a factor:
x3−2x2−11x+12=(x−1)(x2−x−12)
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