find integrating factor
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The given linear differential equation can be supposed to be one in y.
So, the given equation is
dy/dx - (x/1+x^2)y = 0
Now,
the Integrating factor of this equation is
e^ integral of -x/1+x^2 dx
= e^ -1/2 ln(1+x^2)
= 1/√1+x^2
So, 1/√1+x^2 will be the integrating factor of this equation and consequently the solution this differential equation will be
y*1/√1+x^2 = constant
or,
y = C √1+x^2
Hope this helps you !
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