find integration of 2x-5/xsquare-5x+2
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I hope it is helpful to you
Step-by-step explanation:
f(x) = (2x-5) /(x^2 -5x + 6)
F(x)= intg f(x) = intg (2x-5)/(x^2 - 5x + 6)
Let u = x^2 - 5x + 6
==> du = (2x - 5) dx
F(x) = intg du/u
= ln u
= ln (x^2 -5x +6)
F(1) = ln (1-5+6) = ln 2
F(0) = ln (0-0+6) = ln 6
Then the definite intergral = ln 2 - ln 6
= ln 2/6
= ln 1/3
= -ln3
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