find integration of cosx /cos 3x dx
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Step-by-step explanation:
I found: ∫cos(3x)dx=13sin(3x)+c
Explanation:
Considering:
∫cos(3x)dx=
we can set 3x=t
so: x=t3
and: dx=13dt
The integral becomes:
∫13cos(t)dt=13sin(t)+c
going back to x:
we know that t=3x:
=13sin(3x)+c
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