Question

find integration of sin 4x dx​

Answer 1

Answer:

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Step-by-step explanation:

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Answer 2

Answer:

∫sin

4

xdx

∫sin

3

x.sinxdx

Since sin

3

x=3sinx−4sin

3

x

⟹sin

3

x=

4

3sinx−sin3x

4

1

∫(3sinx−sin3x)sinxdx

=

4

1

∫(3sin

2

x−sin3xsinx)dx

=

4

1

∫(3(

2

1−cos2x

)−

2

cos2x−cos4x

)dx

=

8

1

(3x−2sin2x+

4

1

sin4x)

=

8

3x

−

4

1

sin2x+

32

1

sin4x