Question

find integration of (x-1)^4​

Answer 1

Answer:

let x-1 = t

dt = dx

So,

$= > int . \: \: of \: {(x - 1)}^{4} =int \: . \: of \: {t}^{4}$

int of t⁴ =

$= > \frac{ {t}^{5} }{5}$

$= > \frac{ {(x - 1)}^{5} }{5}$

Hope this answer helps you ^_^ !

Answer 2

Answer:

{(x-1)^5(x^2-2x)}/10+C

Step-by-step explanation:

(x-1)^4 dx

= {(x-1)^4+1/4+1}{(x^1+1/1+1)-x}+C

={(x-1)^5/5}(x^2/2-x)+C

={(x-1)^5/5}{(x^2-2x)/2}+C

={(x-1)^5(x^2-2x)}/10+C