find integration of x^2/(x-1)^3.(x+1)
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Answer:
∫(x−1)(x−2)(x−3)3x−1dx
(x−1)(x−2)(x−3)3x−1=x−1a+x−2b+x−bc
a=(1−2)(1−3)3(1)−1=−1(−2)2=1
b=(2−1)(2−3)3(2)−1=−15=−5
c=(3−1)(3−2)3(3)−1=2×18=4
=x−11−x−25+x−34
∫
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