Question

find integration of x cosx dx

Answer 1

hii... here is ur answer

Answer 2

》》》Hope its helps You《《《
☆Firstly, let's split the equation "xcosx" into two parts to integrate them separately.

Let u=x and dv/dx=cosx 2)As the integral of x is 1, du/dx=1 3)To find v, we integrate cosx to get v=sinx
Using the formula: The integral of x.dv/dx=uv-integral of v.du/dx

So, to reiterate we have: u=x du/dx=1 v=cosx dv/dx=sinx

So, using the formula, we need to find uv and the integral of v.du/dx

uv=x.sinx=xsinx
v.du/dx=sinx.1=sinx
By using the formula as listed above:

xsinx-integral(sinx)= xsinx-(-cosx)+c= xsinx+cosx+c
Therefore, the answer is xsinx+cosx+c