find intensity of electricity Field at a point on the axis of the ring
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Answer:
expression of electric field on the axis of the ring is given by, E = Kqx/(R² + x²)^(3/2) see the figure, here a ring is placed and a point located in its axis ( x unit away from the centre of the ring.)
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Explanation:
expression of electric field on the axis of the ring is given by, E = Kqx/(R² + x²)^(3/2) see the figure, here a ring is placed and a point located in its axis ( x unit away from the centre of the ring.)
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