Find inverse of 5 modulo 23 using Fermat’s theorem
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If I have a general modulo equation:
What is the fastest way to solve it? My initial thought was:
5x+1≡2(mod6)5x+1≡2(mod6)⇔5x+1−1≡2−1(mod6)⇔5x+1−1≡2−1(mod6)⇔5x≡1(mod6)⇔5x≡1(mod6)Then solve for the inverse of 55 modulo 6. Is it a right approach?
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