find is circumcentre of the triangle whose vertices are of 1, 3 and minus 3, 5 and 5, - 1
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Let,
A(1,3) B(3,5) C(5,-1).
X1 = 1 , X2= 3 , X3 =5, Y1 = 3 , Y2 = 5, Y3 = -1
BY USING DISTANCE FORMULA.
FIND THE DISTANCE BETWEEN AB, BC,AC
AB² = (X2-X1)²+(Y2-Y1)².
SIMILARLY,
BC² =( X2-X3)²+(Y2-Y3)².
AC²= (X3-X1)+(Y3-Y1)
USING FORMULA FIND THE DISTANCE OF THESE POINTS.
AFTER FINDING DISTANCE BETWEEN THESE POINTS.
ADD THEIR DISTANCE,
AB+BC+AC
A(1,3) B(3,5) C(5,-1).
X1 = 1 , X2= 3 , X3 =5, Y1 = 3 , Y2 = 5, Y3 = -1
BY USING DISTANCE FORMULA.
FIND THE DISTANCE BETWEEN AB, BC,AC
AB² = (X2-X1)²+(Y2-Y1)².
SIMILARLY,
BC² =( X2-X3)²+(Y2-Y3)².
AC²= (X3-X1)+(Y3-Y1)
USING FORMULA FIND THE DISTANCE OF THESE POINTS.
AFTER FINDING DISTANCE BETWEEN THESE POINTS.
ADD THEIR DISTANCE,
AB+BC+AC
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