Question

find it. and get a reward​

Answer 1

Answer:

$we \: know \: the \: formula \\ (x - y) {}^{3} = x {}^{3} - y {}^{3} - 3xy(x - y) \\ therefore \: \\ according \: to \: question \\ x - \frac{1}{x} = \frac{1}{3} \\ now \\ (x - \frac{1}{x}) {}^{3} = x {}^{3} - \frac{1}{x {}^{3} } - 3(x - \frac{1}{x}) \\ ( \frac{1}{3}) {}^{3} = x {}^{3} - \frac{1}{x {}^{3} } - 3 \times \frac{1}{3 } \\ \frac{1}{27} = x {}^{3} - \frac{1}{x {}^{3} } - 1 \\ \frac{1}{27} + 1 = x {}^{3} - \frac{1}{x {}^{3} } \\ x {}^{3} - \frac{1}{x {}^{3} } = \frac{28}{27} ans......$

this is your answer.

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