find it and prove it is a isosceles
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Hi friend
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Your answer
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Given that : - BD and CE are attitudes of the ∆ABC, and BD = CE.
To prove : - ∆ABC is an isosceles triangle.
Then,
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In ∆BEC and ∆BDC, we have ,
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CE = BD (Given)
BC = BC (Common)
Angle BEC = Angle BDC (90° each)
So, ∆BEC is congruent to ∆BDC .(By S.A.S. criteria)
So, Angle EBC = Angle DBC (By C.P.C.T.)
Therefore,
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In ∆ABC , Angle B = Angle C
Therefore, ∆ABC is an isosceles triangle because the base angles are equal so , AB = AC.
PROVED.
HOPE IT HELPS
--------------
Your answer
----------------------
Given that : - BD and CE are attitudes of the ∆ABC, and BD = CE.
To prove : - ∆ABC is an isosceles triangle.
Then,
-----------
In ∆BEC and ∆BDC, we have ,
----------------------------------------------
CE = BD (Given)
BC = BC (Common)
Angle BEC = Angle BDC (90° each)
So, ∆BEC is congruent to ∆BDC .(By S.A.S. criteria)
So, Angle EBC = Angle DBC (By C.P.C.T.)
Therefore,
-------------------
In ∆ABC , Angle B = Angle C
Therefore, ∆ABC is an isosceles triangle because the base angles are equal so , AB = AC.
PROVED.
HOPE IT HELPS
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