Question

find it factorise x⁸-1​ ​

Answer 1

Answer:

answer is ( x⁴-1) ( x⁴+1)

hope it helps you

Answer 2

Hey User!!

Here's your answer.

$= > {x}^{8} - 1$

$= > ({x}^{4})^{2} - 1$

$= > ( {x}^{4} + 1)( {x}^{4} - 1)$

$= > ( {x}^{4} + 1) (( {x}^{2})^{2} - 1)$

$= > ({x}^{4} + 1)( {x}^{2} + 1)( {x}^{2} - 1)$

$= > ( {x}^{4} + 1)(( {x}^{2} + 1)(x + 1)(x - 1))$

Hope it helps!!

@charlie16.