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Answer:
A (0,0) B ( 1, 0) C ( 0, 1 )
for first side
firstly we will find the distance between A and B
{ A = ( x1 = 0 , y1 = 0) }
{B = ( x2= 1 , y2 = 0)}
distance formula =√( x2 - x1 ) ^ 2 +(y2 - y1) ^ 2
= √ (1 - 0 ) ^2 + ( 0 - 0 )^2
=√ 1 + 0
=√1
ones side = 1
for second side
B =( 1 , 0) C = ( 0 , 1 )
{B = (x 3 = 1 , y3 = 0) }
{ C = ( x4 = 0 , y 4 = 1 ) }
using distance formula
distance formula = √ ( x 4 -x 3)^2 + ( y 4 - y 3 )^2
= √ (0 - 1 ) ^2 + ( 1 - 0 ) ^ 2
= √ ( -1 ) ^2 + ( 1)^2
= √ 1 + 1
= √2
second side is √ 2
for third side
C = ( 0 ,1 ) A = ( 0, 0)
{ C = ( x 4 = 0 , y4 = 1 ) }
{A= ( x1= 0 , y 1= 0) }
using distance formula
distance formula = √ ( x1 - x4 ) ^ 2 + ( y1 - y 4)^2
= √ ( 0-0)^2 + ( 0 -1 ) ^ 2
= √ (-1) ^2
= √ 1
=1
third side is 1 ...
perimeter of triangle = sum of all sides
= 1+√2 + 1
= 2√2
Step-by-step explanation: