Math, asked by januhari2624, 9 months ago

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Answered by pulakmath007
1

Answer:

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Answered by MrSharib
3

Answer:

A (0,0) B ( 1, 0) C ( 0, 1 )

for first side

firstly we will find the distance between A and B

{ A = ( x1 = 0 , y1 = 0) }

{B = ( x2= 1 , y2 = 0)}

distance formula =√( x2 - x1 ) ^ 2 +(y2 - y1) ^ 2

= √ (1 - 0 ) ^2 + ( 0 - 0 )^2

=√ 1 + 0

=√1

ones side = 1

for second side

B =( 1 , 0) C = ( 0 , 1 )

{B = (x 3 = 1 , y3 = 0) }

{ C = ( x4 = 0 , y 4 = 1 ) }

using distance formula

distance formula = √ ( x 4 -x 3)^2 + ( y 4 - y 3 )^2

= √ (0 - 1 ) ^2 + ( 1 - 0 ) ^ 2

= √ ( -1 ) ^2 + ( 1)^2

= √ 1 + 1

= √2

second side is √ 2

for third side

C = ( 0 ,1 ) A = ( 0, 0)

{ C = ( x 4 = 0 , y4 = 1 ) }

{A= ( x1= 0 , y 1= 0) }

using distance formula

distance formula = √ ( x1 - x4 ) ^ 2 + ( y1 - y 4)^2

= √ ( 0-0)^2 + ( 0 -1 ) ^ 2

= √ (-1) ^2

= √ 1

=1

third side is 1 ...

perimeter of triangle = sum of all sides

= 1+2 + 1

= 22

Step-by-step explanation:

hope it helps

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