Question

Find its
ente
2. Find the equation of the circle the end points of whose diameter are the centres of the
circles x2 + y2 + 6x – 14y - 1 = 0 and x2
+ y2 - 4x + 10y - 2=0.
sides of a square are 7-6​

Answer 1

Answer:

34_7

Step-by-step explanation:

:&+)794$&) xdrigddx vm #+);$48(:_

Answer 2

Answer:

Centre of first circle

x2+y2+16x−14y−1=0.is(−g,−f)⇒(−8,7)→PForIICircle:Centre→(2,−5)→QEquationofcirclewithP&Qasdiametricendpoints:Centre→(2−8+2,27−5)⇒(−3,1).radius=21(2+8)2+(−5−7)2=21100+144=2244.⇒(x+3)2+(y−1)2=4244⇒(x+3)2+(y−1)2=61