Question

find its n th term.....​

Answer 1

Step-by-step explanation:

$4 {n}^{2} + 5n - 636 = 0 \\ \\ 4 {n}^{2} - 48n + 53n - 636 = 0 \\ \\ 4n(n - 12) + 53(n - 12) = 0 \\ \\ (4n + 53)(n - 12) = 0 \\ \\ 4n + 53 = 0 \: \: \: or \: \: \: n - 12 = 0 \\ \\ \therefore \: n = \frac{ - 53}{4 } \: \: \: or \: \: \: n = 12$

your answer n=12

Answer 2

Step-by-step explanation:

Attachment se aage ka solution

$4 {n}^{2} + 5n - 636 \\ 4 {n}^{2} + (53 - 48)n - 636 \\ 4 {n}^{2} + 53n - 48n - 636 \\ n(4n + 53) - 12(4n - 53) \\ (4n + 53)(n - 12)$

There are two solutions for n

n =-53/4 and n=12

n=-53/4 is not possible

So, n=12

So, nth term is 12th term

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