Find its perimeter.
5.) Find the perimeters of (i) A ABE (ii) the rectangle BCDE in this
figure. Whose perimeter is greater?
3
in a frame. The picture is 7- cm wide.
Answers
Correct Question:-
Find the perimeter of (i) Δ ABE, (ii) the rectangle BCDE in this figure. Whose perimeter is greater?
Solution:-
(i) In Δ ABE, AB = 5/2 cm, BE = 2 cm, AE = 3 cm
The perimeter of Δ ABE = AB + BE + AE
= 5/2 + 2 + 3
= 5/2 + 11/4 + 18/5
= (5 * 10 + 11 * 5 + 18 *4)/20
= (50 + 55 + 72)/20
= 177/20
= 8 cm
Thus, the perimeter of Δ ABE is 8 cm.
(ii) In rectangle BCDE, BE = 2 cm, ED = 7/6
Perimeter of rectangle = 2(Length + Breath)
= 2(2 + 7/6)
= 2(11/4 + 7/6)
= 2[(11 * 3 + 7 * 2)/12]
= 2[(33 + 14)/12]
= 2(47/12)
= 47/6
= 7
Thus, the perimeter of rectangle BCDE is 7 cm.
Since, 8 cm > 7 cm
Therefore, the perimeter of Δ ABE is greater than that of rectangle BCDE.
I hope it's help you...☺
