Find its perimeter.
5. Find the perimeters of (i) AABE (ii) the rectangle BCDE in this
figure. Whose perimeter is greater?
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Answers
Answer:Sides of Δ ABE : -
3 1/3 cm,
2 1/5 cm,
4 2/3 cm,
Perimeter of ΔABE = sum of all sides,
Perimeter of ΔABE = 3 1/3 cm+2 1/5 cm+4 2/3 cm,
Perimeter of ΔABE = 10 / 3 cm + 11 / 5 cm + 14 / 3 cm,
,
Perimeter of ΔABE = 50 / 15 + 33 / 15 + 70 / 15 cm,
Perimeter of ΔABE = ( 50 + 33 + 70 ) / 15 cm,
Perimeter of ΔABE = 153 / 15 cm.
( ii ) : BCDE,
Perimeter of rectangle = 2( length + breadth ),
Perimeter of rectangle = 2(2 1/5 cm+1 2/3 cm ),
Perimeter of rectangle = 2( 11 / 5 cm + 5 / 3 cm ),
,
Perimeter of rectangle = 2( 33 / 15 cm + 25 / 15 cm ),
Perimeter of rectangle = 2( 58 / 15 ),
Perimeter of rectangle = 116 / 15 cm.
As 153 / 15 > 116 / 15. Triangular figure has greater perimeter and by ( 153 - 116 ) / 15 ; 37 / 15.
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