Math, asked by manojsharma64, 8 months ago


Find its perimeter.
5. Find the perimeters of (i) AABE (ii) the rectangle BCDE in this
figure. Whose perimeter is greater?
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Answers

Answered by itsbiswaa
3

Answer:Sides of Δ ABE : -

3 1/3 cm,

2 1/5 cm,

4 2/3 cm,

Perimeter of ΔABE  = sum of all sides,

Perimeter of ΔABE  = 3 1/3 cm+2 1/5 cm+4 2/3 cm,

Perimeter of ΔABE = 10 / 3 cm + 11 / 5 cm + 14 / 3 cm,

,

Perimeter of ΔABE = 50 / 15 + 33 / 15 + 70 / 15 cm,

Perimeter of ΔABE = ( 50 + 33 + 70 ) / 15 cm,

Perimeter of ΔABE = 153 / 15 cm.

( ii ) : BCDE,

Perimeter of rectangle = 2( length + breadth ),

Perimeter of rectangle = 2(2 1/5 cm+1 2/3 cm ),

Perimeter of rectangle = 2( 11 / 5 cm + 5 / 3 cm ),

,

Perimeter of rectangle = 2( 33 / 15 cm + 25 / 15 cm ),

Perimeter of rectangle = 2( 58 / 15 ),

Perimeter of rectangle = 116 / 15 cm.

As 153 / 15 > 116 / 15. Triangular figure has greater perimeter and by ( 153 - 116 ) / 15  ; 37 / 15.

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