Question

find its perimeter. length 13 1/5 and breadth 10 1/2​

Answer 1

Answer:

$perimeter = 2(length + breadth)$

$p = 2( \frac{66}{5} + \frac{21}{2} )$

$p = 2( \frac{132 + 105}{10} )$

$p = 2 \times \frac{237}{10 } = \frac{237}{5} = 47 \frac{2}{5}$

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Answer 2

Answer:

Step-by-step explanation:

perimeter = 2[l+b]

length= 13  1/5 =66/5

breadth = 10  1/2 = 21/2

perimeter = 2 [ 66/5 +21/2]

                  =2[ 132/10 +105/10]

                   =2 [237/10 ]

                    = 2* 237/ 10

                     =237/ 5  

                     =47.4

∴ perimeter = 47.4