Question

Find K (-2)^K+1 × (-2)^5 = (-2)^7

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Answer 1

Answer:

Since points are collinear,

so, x1  (y2 −y3 )+x  2 (y3  −y  1 )+x  3 (y1 −y  2 )=0

Take (7,−2) as (x1 ,y1 ), (5,1) as (x  2,y2) and (3,k) as (x  3 ,y3​), we have

7(1−k)+5(k+2)+3(−2−1)=0

⇒ 7−7k+5k+10−9=0

⇒ 2k=8  

⇒ k=4